Search in Rotated Sorted Array easy solution

 def serach(nums,l,u,target):

    if target in nums[l:u+1]:


        for i in range(l,u):

            if target==nums[i]:

                return nums.index(nums[i])

    else:

        for i in range(u,len(nums)):

            if target==nums[i]:

                return nums.index(nums[i])

        else:

            return -1

            

nums=[4,0,6,7,8,1,2]

l=0

u=(l+len(nums))//2

target=1

print(serach(nums,l,u,target))


output=5

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